Ch-9: Some Applications of Trigonometry30 Questions
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1. The angle formed by the line of sight with the horizontal when the point being viewed is above the horizontal level is called:
A. Angle of depression
B. Angle of elevation
C. Obtuse angle
D. Acute angle
Answer: B. Angle of elevation
Explanation: When an object is above the horizontal plane, the angle between the line of sight and the horizontal line is called the angle of elevation.
2. If a tower is 30 m high and the angle of elevation of its top from a point on the ground is 45°, the distance of the point from the base of the tower is:
A. 15 m
B. 30 m
C. 30√3 m
D. 15√3 m
Answer: B. 30 m
Explanation: tan 45° = Height / Distance ⇒ 1 = 30 / Distance ⇒ Distance = 30 m.
3. A pole 6 m high casts a shadow 2√3 m long on the ground, then the Sun's elevation is:
4. If the height of a vertical pole and the length of its shadow on the ground are equal, then the angle of elevation of the Sun is:
A. 30°
B. 45°
C. 60°
D. 90°
Answer: B. 45°
Explanation: tan θ = Height / Shadow = h / h = 1 ⇒ θ = 45°.
5. The angle of depression of an object on the ground from the top of a 75 m high cliff is 30°. The distance of the object from the foot of the cliff is:
A. 75 m
B. 75√3 m
C. 25√3 m
D. 150 m
Answer: B. 75√3 m
Explanation: tan 30° = 75 / x ⇒ 1/√3 = 75 / x ⇒ x = 75√3 m.
6. A ladder 10 m long reaches a window 8 m above the ground. The distance of the foot of the ladder from the base of the wall is:
A. 2 m
B. 4 m
C. 6 m
D. 8 m
Answer: C. 6 m
Explanation: By Pythagoras theorem: Distance = √(10² - 8²) = √(100 - 64) = √36 = 6 m.
7. A kite is flying at a height of 60 m above the ground attached to a string inclined at 60° to the horizontal. Assuming string is straight, its length is:
A. 40√3 m
B. 30√3 m
C. 120 m
D. 80 m
Answer: A. 40√3 m
Explanation: sin 60° = Height / Length ⇒ √3/2 = 60 / L ⇒ L = 120 / √3 = 40√3 m.
8. If the angle of elevation of the top of a tower from a point on the ground is 30° and on walking 20 m towards the tower it becomes 60°, the height of tower is:
A. 10 m
B. 10√3 m
C. 20√3 m
D. 30 m
Answer: B. 10√3 m
Explanation: Let height be h. tan 60° = h/x ⇒ x = h/√3. tan 30° = h/(x + 20) ⇒ 1/√3 = h/(h/√3 + 20) ⇒ h = 10√3 m.
9. The shadow of a tower standing on a level ground is found to be 40 m longer when the Sun's altitude is 30° than when it is 60°. The height of the tower is:
A. 20√3 m
B. 40√3 m
C. 10√3 m
D. 20 m
Answer: A. 20√3 m
Explanation: Using relation h = d / (cot θ1 - cot θ2) = 40 / (cot 30° - cot 60°) = 40 / (√3 - 1/√3) = 40 / (2/√3) = 20√3 m.
10. Line of sight is the line drawn from the eye of an observer to the:
A. Top of the object
B. Point in the object viewed by the observer
C. Base of the object
D. Horizontal plane
Answer: B. Point in the object viewed by the observer
Explanation: By definition, line of sight connects the observer's eye to the specific point being viewed on the object.
11. A 1.5 m tall observer is 28.5 m away from a chimney. The angle of elevation of top of chimney from her eyes is 45°. Height of chimney is:
A. 28.5 m
B. 30 m
C. 27 m
D. 31.5 m
Answer: B. 30 m
Explanation: tan 45° = (H - 1.5) / 28.5 ⇒ 1 = (H - 1.5) / 28.5 ⇒ H = 28.5 + 1.5 = 30 m.
12. The angle of elevation of the top of a building from the foot of a tower is 30° and from top of building to foot of tower is 60°. If tower is 50 m high, height of building is:
A. 16.67 m
B. 25 m
C. 50/3 m
D. Both A and C
Answer: D. Both A and C
Explanation: Distance x = 50 / tan 60° = 50/√3. Height of building h = x tan 30° = (50/√3) × (1/√3) = 50/3 m = 16.67 m.
13. The angle of elevation of the Sun increases from 30° to 60°, the length of shadow of a tower:
A. Increases
B. Decreases
C. Remains same
D. Doubles
Answer: B. Decreases
Explanation: As the angle of elevation increases towards 90°, the length of the shadow gets shorter (decreases).
14. An observer on top of a 100 m high lighthouse sees a boat at an angle of depression of 30°. Distance of boat from lighthouse base is:
A. 100 m
B. 100/√3 m
C. 100√3 m
D. 200 m
Answer: C. 100√3 m
Explanation: tan 30° = 100 / x ⇒ 1/√3 = 100 / x ⇒ x = 100√3 m.
15. If a ratio of length of a rod and its shadow is 1 : √3, then the angle of elevation of the sun is:
A. 30°
B. 45°
C. 60°
D. 90°
Answer: A. 30°
Explanation: tan θ = Rod / Shadow = 1 / √3 ⇒ θ = 30°.
16. A circus artist is climbing a 20 m long rope tightly stretched from top of a vertical pole to ground. If angle made with ground is 30°, height of pole is:
A. 10 m
B. 20 m
C. 10√3 m
D. 5 m
Answer: A. 10 m
Explanation: sin 30° = h / 20 ⇒ 1/2 = h / 20 ⇒ h = 10 m.
17. A tree breaks due to a storm and the broken top touches ground making an angle of 30° with it. Distance from foot to top touching ground is 8 m. Total height of tree is:
A. 8√3 m
B. 8/√3 m
C. 16/√3 m
D. 24 m
Answer: A. 8√3 m
Explanation: Standing part = 8 tan 30° = 8/√3. Broken part = 8 / cos 30° = 16/√3. Total = 24/√3 = 8√3 m.
18. The tops of two poles of height 20 m and 14 m are connected by a wire. If wire makes an angle of 30° with horizontal, length of wire is:
A. 6 m
B. 8 m
C. 10 m
D. 12 m
Answer: D. 12 m
Explanation: Difference in height = 20 - 14 = 6 m. sin 30° = 6 / L ⇒ 1/2 = 6 / L ⇒ L = 12 m.
19. From a point P on level ground, the angle of elevation of top of a tower is 30°. If tower is 100 m high, distance of P from top of tower is:
A. 100 m
B. 200 m
C. 100√3 m
D. 50 m
Answer: B. 200 m
Explanation: sin 30° = Height / Distance from top ⇒ 1/2 = 100 / D ⇒ D = 200 m.
20. The angle of elevation of top of a tower from two points at distances 'a' and 'b' from base and in same line are complementary. Height of tower is:
A. ab
B. √(a/b)
C. √(ab)
D. a/b
Answer: C. √(ab)
Explanation: tan θ = h/a and tan(90°-θ) = cot θ = h/b. Multiplying gives tan θ × cot θ = h²/ab ⇒ 1 = h²/ab ⇒ h = √(ab).
21. Angle of elevation of top of a building from a point 50 m away from its foot is 60°. Height of building is:
A. 50 m
B. 50√3 m
C. 50/√3 m
D. 25√3 m
Answer: B. 50√3 m
Explanation: tan 60° = h / 50 ⇒ √3 = h / 50 ⇒ h = 50√3 m.
22. If two towers of height h1 and h2 subtend angles of 60° and 30° respectively at mid-point of line joining their feet, then h1 : h2 is:
A. 1 : 2
B. 1 : 3
C. 3 : 1
D. 2 : 1
Answer: C. 3 : 1
Explanation: Let midpoint distance be x. h1 = x tan 60° = x√3, h2 = x tan 30° = x/√3. h1/h2 = (x√3) / (x/√3) = 3/1 = 3 : 1.
23. When object is below horizontal level, angle between line of sight and horizontal line is called:
A. Angle of elevation
B. Angle of depression
C. Right angle
D. Straight angle
Answer: B. Angle of depression
Explanation: Looking down below horizontal level forms the angle of depression.
24. A cable tower of height 7 m has top of a building at angle of elevation 60° and foot at depression 45°. Height of tower is:
A. 7(√3 + 1) m
B. 7(√3 - 1) m
C. 14 m
D. 7√3 m
Answer: A. 7(√3 + 1) m
Explanation: Distance between them = 7 / tan 45° = 7 m. Height above building = 7 tan 60° = 7√3 m. Total height = 7 + 7√3 = 7(√3 + 1) m.
25. A statue 1.6 m tall stands on top of a pedestal. From a point on ground, elevation of top of statue is 60° and top of pedestal is 45°. Height of pedestal is:
A. 0.8(√3 + 1) m
B. 0.8(√3 - 1) m
C. 1.6(√3 + 1) m
D. 1.6(√3 - 1) m
Answer: A. 0.8(√3 + 1) m
Explanation: Let h be height. (h + 1.6)/h = tan 60°/tan 45° = √3 ⇒ h(√3 - 1) = 1.6 ⇒ h = 1.6/(√3 - 1) = 0.8(√3 + 1) m.
26. If the shadow of a tower is 1/√3 times its height, then the angle of elevation of the sun is:
A. 30°
B. 45°
C. 60°
D. 90°
Answer: C. 60°
Explanation: tan θ = h / (h / √3) = √3 ⇒ θ = 60°.
27. An observer 1.7 m tall stands 20 m away from a tower 21.7 m high. The angle of elevation of top of tower from observer's eye is:
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