1. Who discovered the electron?
A. J.J. Thomson
B. Ernest Rutherford
C. James Chadwick
D. John Dalton
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Answer: A. J.J. Thomson
Explanation: J.J. Thomson discovered the electron in 1897 through cathode ray discharge tube experiments.
2. The neutron was discovered by:
A. James Chadwick
B. J.J. Thomson
C. Ernest Rutherford
D. Niels Bohr
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Answer: A. James Chadwick
Explanation: James Chadwick discovered neutrons in 1932 by bombarding beryllium with alpha particles.
3. What is the charge-to-mass ratio (e/m) of an electron?
A. 1.758820 × 10¹¹ C/kg
B. 1.602 × 10⁻¹⁹ C/kg
C. 9.109 × 10⁻³¹ C/kg
D. 1.758820 × 10⁸ C/kg
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Answer: A. 1.758820 × 10¹¹ C/kg
Explanation: J.J. Thomson measured the charge-to-mass ratio of electrons to be 1.758820 × 10¹¹ C/kg.
4. Rutherford's alpha-particle scattering experiment led to the discovery of the:
A. Atomic nucleus
B. Electron
C. Proton
D. Neutron
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Answer: A. Atomic nucleus
Explanation: The scattering of alpha particles at large angles proved that most mass and positive charge are concentrated in a tiny nucleus.
5. The principal quantum number (n) determines the:
A. Size and energy of the orbital
B. Shape of the orbital
C. Spatial orientation of the orbital
D. Spin orientation of the electron
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Answer: A. Size and energy of the orbital
Explanation: The principal quantum number (n) defines the main energy level or shell and determines its size.
6. The shape of a p-orbital is:
A. Dumb-bell
B. Spherical
C. Double dumb-bell
D. Complex
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Answer: A. Dumb-bell
Explanation: s-orbitals are spherical, p-orbitals are dumb-bell shaped, and d-orbitals are double dumb-bell shaped.
7. How many subshells are present in the shell with principal quantum number n = 3?
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Answer: A. 3
Explanation: For n = 3, l can take values 0, 1, and 2, corresponding to 3 subshells (3s, 3p, 3d).
8. What is the maximum number of electrons that can be accommodated in a d-subshell?
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Answer: A. 10
Explanation: A d-subshell has 5 orbitals (2l + 1), and each orbital can hold 2 electrons, making a total of 10 electrons.
9. Which rule states that no two electrons in an atom can have the same set of four quantum numbers?
A. Pauli Exclusion Principle
B. Aufbau Principle
C. Hund's Rule of Maximum Multiplicity
D. Heisenberg Uncertainty Principle
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Answer: A. Pauli Exclusion Principle
Explanation: Wolfgang Pauli stated that two electrons in an atom cannot share all four identical quantum numbers.
10. According to the Aufbau Principle, orbitals are filled in order of their:
A. Increasing energy
B. Decreasing energy
C. Increasing size
D. Decreasing size
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Answer: A. Increasing energy
Explanation: The Aufbau principle dictates that electrons fill lower-energy atomic orbitals before higher-energy ones.
11. What is the total number of orbitals in a shell with principal quantum number n?
A. n²
B. 2n²
C. 2n
D. n + 1
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Answer: A. n²
Explanation: The total number of orbitals in an n-th energy level is given by n² (and maximum electrons = 2n²).
12. De Broglie wavelength of a particle is given by the expression:
A. λ = h / mv
B. λ = mv / h
C. λ = h / m
D. λ = h / v
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Answer: A. λ = h / mv
Explanation: Louis de Broglie proposed that dual matter waves have a wavelength λ = h/p = h/(mv).
13. Which quantum number specifies the spatial orientation of an orbital?
A. Magnetic quantum number (mₗ)
B. Principal quantum number (n)
C. Azimuthal quantum number (l)
D. Spin quantum number (mₛ)
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Answer: A. Magnetic quantum number (mₗ)
Explanation: The magnetic quantum number (mₗ) describes the orientation of the orbital in three-dimensional space.
14. Isobars are atoms having the same:
A. Mass number but different atomic numbers
B. Atomic number but different mass numbers
C. Number of neutrons
D. Number of protons
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Answer: A. Mass number but different atomic numbers
Explanation: Isobars have the same mass number (A) but different atomic numbers (Z).
15. The correct electronic configuration of Chromium (Cr, Z = 24) is:
A. [Ar] 3d⁵ 4s¹
B. [Ar] 3d⁴ 4s²
C. [Ar] 3d⁶ 4s⁰
D. [Ar] 3d³ 4s² 4p¹
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Answer: A. [Ar] 3d⁵ 4s¹
Explanation: Chromium gains extra stability by attaining a half-filled 3d⁵ configuration rather than 3d⁴ 4s².
16. What is the value of Azimuthal quantum number (l) for a d-subshell?
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Answer: A. 2
Explanation: Subshell designations are l = 0 (s), l = 1 (p), l = 2 (d), and l = 3 (f).
17. Heisenberg's Uncertainty Principle is mathematically stated as:
A. Δx · Δp ≥ h / (4π)
B. Δx · Δp = h / (2π)
C. Δx · Δp ≤ h / (4π)
D. Δx · Δv ≥ h / (2π)
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Answer: A. Δx · Δp ≥ h / (4π)
Explanation: It states that position (Δx) and momentum (Δp) of a microscopic particle cannot be simultaneously determined with absolute precision.
18. The line spectrum of hydrogen was first successfully explained by:
A. Niels Bohr
B. J.J. Thomson
C. Ernest Rutherford
D. Erwin Schrödinger
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Answer: A. Niels Bohr
Explanation: Niels Bohr applied quantum theory to model hydrogen and successfully explained its discrete emission spectrum.
19. Which spectral series of hydrogen atom lies in the visible region?
A. Balmer series
B. Lyman series
C. Paschen series
D. Brackett series
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Answer: A. Balmer series
Explanation: Lyman is UV, Balmer is Visible, and Paschen/Brackett/Pfund are in the Infrared region.
20. The maximum number of electrons in a main shell is given by:
A. 2n²
B. n²
C. 2n + 1
D. 4l + 2
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Answer: A. 2n²
Explanation: A shell with principal quantum number 'n' can hold a maximum of 2n² electrons.
21. Isotopes are atoms of the same element having:
A. Same atomic number but different mass numbers
B. Same mass number but different atomic numbers
C. Same number of neutrons
D. Different number of protons
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Answer: A. Same atomic number but different mass numbers
Explanation: Isotopes have equal protons (same atomic number) but differing numbers of neutrons (different mass numbers).
22. The energy of a photon of frequency ν is given by Planck's equation:
A. E = hν
B. E = mc²
C. E = h / ν
D. E = ν / h
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Answer: A. E = hν
Explanation: Max Planck postulated that radiant energy is emitted or absorbed in discrete packets (quanta) with energy E = hν.
23. Electronic configuration of Copper (Cu, Z = 29) is:
A. [Ar] 3d¹⁰ 4s¹
B. [Ar] 3d⁹ 4s²
C. [Ar] 3d⁸ 4s²
D. [Ar] 3d¹⁰ 4s²
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Answer: A. [Ar] 3d¹⁰ 4s¹
Explanation: Copper achieves high stability by completely filling its 3d subshell (3d¹⁰ 4s¹ instead of 3d⁹ 4s²).
24. What is the number of radial nodes for a 3p orbital?
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Answer: A. 1
Explanation: Number of radial nodes = n - l - 1. For 3p orbital, n = 3, l = 1, so Radial Nodes = 3 - 1 - 1 = 1.
25. Species having the same number of electrons are called:
A. Isoelectronic species
B. Isotopes
C. Isobars
D. Isotones
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Answer: A. Isoelectronic species
Explanation: Ions or atoms having identical numbers of total electrons (e.g., Na⁺, F⁻, Ne) are isoelectronic.
26. Which orbital has a spherical shape?
A. s-orbital
B. p-orbital
C. d-orbital
D. f-orbital
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Answer: A. s-orbital
Explanation: All s-orbitals (1s, 2s, 3s, etc.) are spherically symmetrical around the nucleus.
27. Which rule states that electron pairing in degenerate orbitals does not take place until each orbital is singly occupied?
A. Hund's Rule
B. Pauli Exclusion Principle
C. Aufbau Principle
D. Heisenberg Principle
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Answer: A. Hund's Rule
Explanation: Hund's Rule of Maximum Multiplicity dictates that degenerate orbitals are filled singly first with parallel spins.
28. Photoelectric effect was successfully explained by Albert Einstein using:
A. Quantum theory of light
B. Wave theory of light
C. Classical electrodynamics
D. Rutherford model
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Answer: A. Quantum theory of light
Explanation: Einstein explained photoelectric effect by proposing that light behaves as packets of energy called photons.
29. The value of Planck's constant (h) is:
A. 6.626 × 10⁻³⁴ J·s
B. 6.022 × 10²³ J·s
C. 1.602 × 10⁻¹⁹ J·s
D. 9.109 × 10⁻³¹ J·s
Show Answer
Answer: A. 6.626 × 10⁻³⁴ J·s
Explanation: Planck's fundamental physical constant has an accepted value of approximately 6.626 × 10⁻³⁴ J·s.
30. What is the maximum number of electrons in an orbital?
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Answer: A. 2
Explanation: According to Pauli's exclusion principle, a single atomic orbital can hold a maximum of 2 electrons with opposite spins.