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NCERT Solutions for Class 9 Science Chapter 4 Structure of the Atom

NCERT Solutions for Class 9 Science Chapter 4 Structure of the Atom covers subatomic particles (electrons, protons, neutrons), Thomson's model, Rutherford's scattering experiment, Bohr's model, electron distribution, valency, atomic number, mass number, isotopes, and isobars.

Overview of Topics & Subtopics (Click to Jump)

1. Charged Particles in Matter & Thomson's Atomic Model

Short Note:

• Subatomic Particles:

  - Electron (e-): Discovered by J.J. Thomson; charge is -1, mass is negligible (1/2000 of a hydrogen atom).

  - Proton (p+): Discovered by E. Goldstein (canal rays); charge is +1, mass is 1 unit.

• Thomson's Model of Atom (Watermelon Model): An atom consists of a positively charged sphere with electrons embedded in it like seeds in a watermelon. Total positive charge equals total negative charge, making the atom electrically neutral.

2. Rutherford's Scattering Experiment & Bohr's Atomic Model

Short Note:

• Rutherford's Gold Foil Experiment: Fast moving alpha (α) particles were bombarded on thin gold foil.

  - Most α-particles passed straight through (most space in an atom is empty).

  - Some were deflected by small angles (positive charge occupies small space).

  - 1 out of 12,000 rebounded back (all positive charge and mass concentrated in a tiny central nucleus).

• Bohr's Model of Atom: Electrons revolve in special discrete orbits (energy levels labeled K, L, M, N or n = 1, 2, 3, 4) without radiating energy.

3. Neutrons & Distribution of Electrons (Bohr-Bury Scheme)

Short Note:

• Neutron (n): Discovered by J. Chadwick in 1932; neutral subatomic particle present in the nucleus (except hydrogen). Mass is nearly equal to a proton.

• Bohr-Bury Rules for Electron Distribution:

  1. Maximum electrons in a shell = 2n2 (K=2, L=8, M=18, N=32).

  2. The outermost orbit can accommodate a maximum of 8 electrons.

  3. Shells are filled in a step-wise manner.

4. Valency, Atomic Number, Mass Number, Isotopes & Isobars

Short Note:

• Valency: Combining capacity of an atom (Valency = valence electrons if ≤ 4; or 8 − valence electrons if > 4).

• Atomic Number (Z): Total number of protons in the nucleus of an atom.

• Mass Number (A): Total number of protons and neutrons (nucleons) in the nucleus.

• Isotopes: Atoms of the same element with the same atomic number (Z) but different mass numbers (A) (e.g., 1H, 2H, 3H).

• Isobars: Atoms of different elements with different atomic numbers but the same mass number (e.g., 40Ca and 40Ar).

Intext Questions - Page Number: 47

Q1: What are canal rays?
Answer: Canal rays are positively charged radiations produced in a discharge tube containing gas at low pressure. They led to the discovery of subatomic particles called protons.
Q2: If an atom contains one electron and one proton, will it carry any charge or not?
Answer: No, the atom will be electrically neutral because the positive charge of one proton (+1) balances the negative charge of one electron (-1).

Intext Questions - Page Number: 49

Q1: On the basis of Thomson’s model of an atom, explain how the atom is neutral as a whole.
Answer: According to Thomson's model, an atom consists of a sphere of positive charge in which negatively charged electrons are embedded. The magnitude of negative and positive charges is equal, making the atom electrically neutral as a whole.
Q2: What are the limitations of Rutherford’s model of the atom?
Answer: According to classical electromagnetic theory, an electron revolving continuously in a circular orbit around the nucleus should continuously lose energy. This would cause the electron to spiral inward and collapse into the nucleus, making the atom unstable. Rutherford's model could not explain this stability.

Textbook Chapter End Exercise Questions

Q1: Compare the properties of electrons, protons and neutrons.
Answer:

• Electron: Charge = −1 unit; Mass = 1/2000 u (negligible); Location = Revolves outside nucleus in shells.

• Proton: Charge = +1 unit; Mass = 1 u; Location = Inside nucleus.

• Neutron: Charge = 0 (Neutral); Mass = 1 u; Location = Inside nucleus.

Q2: Define valency by taking examples of silicon and oxygen.
Answer: Valency is the combining capacity of an atom to achieve a stable octet (8 electrons in outer shell).
• Silicon (Z=14): Electronic configuration = 2, 8, 4. Outer shell has 4 valence electrons. Therefore, Valency of Silicon = 4.
• Oxygen (Z=8): Electronic configuration = 2, 6. Outer shell has 6 valence electrons. Valency = 8 − 6 = 2.
Q3: If number of electrons in an atom is 8 and number of protons is 8, then (i) what is the atomic number of the atom? and (ii) what is the charge on the atom?
Answer:

(i) Atomic Number (Z): Equal to number of protons = 8 (Oxygen).

(ii) Charge: Since number of protons (8) = number of electrons (8), the net charge on the atom is 0 (Neutral).

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Class 9 › Science › Structure of the Atom
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Topics in this chapter: Charged Particles in Matter & Thomson's Atomic ModelRutherford's Scattering Experiment & Bohr's Atomic ModelNeutrons & Distribution of Electrons (Bohr-Bury Scheme)Valency, Atomic Number, Mass Number, Isotopes & Isobars